problem with shell script to send find to awk

[crp]

mDoW="`date | cut -c 1-3`"
mkdir /home/bu_files/$mDoW/
find /mnt/SAC/* -mtime -1 | awk '{print "cp " "\"$_"\" " /home/bu_files/"$mDoW}'

results in

awk: line 1: runaway string constant "$mDoW} ...

Anyone know how to fix it? using Debian Whiskey.

Edited April 25, 2014 by crp

[ebrke]

Does this link help at all:

http://www.gnu.org/software/gawk/manual/html_node/Using-Shell-Variables.html

 

My own shell scripting days are 10+ years in the past, unfortunately.

[jimg]

What are you trying to accomplish with your script?

 

You can the get the day of the week from date without using cut:

 

mDow=$(date +%a)
echo $mDow
Sat

[crp]

What are you trying to accomplish with your script?

 

You can the get the day of the week from date without using cut:

 

mDow=$(date +%a)
echo $mDow
Sat

copy new files from today to a directory with the day's name as part of the directory name.

This is simple enough in the DOS world with xcopy but I can't find an equivalent in Linux.

My quote marks seem to be aligned properly but the macro expansions are not functioning.

[crp]

I gave up on it, after a lot of toil came up with

find /mnt/SAC/* -type f -mtime -1 -exec cp -u -v -b -p --parents {} /home/bu_files/_$mDoW/ \;